4(0.5x)^2=(1/x)^-1

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Solution for 4(0.5x)^2=(1/x)^-1 equation: 



4(0.5x)^2=(1/x)^-1

We move all terms to the left:

4(0.5x)^2-((1/x)^-1)=0



Domain of the equation: x)^-1)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

4(+0.5x)^2-((+1/x)^-1)=0

We multiply all the terms by the denominator


(4(+0.5x)^2)*x)^-1)-((+1=0

We move all terms containing x to the left, all other terms to the right

(4(+0.5x)^2)*x)^-1)-((=-1

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